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Author Topic: I had fractals for lunch (Romanesco cabbage)  (Read 5150 times)
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bib
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« on: February 15, 2009, 07:28:10 PM »

And it tasted very good smiley
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cKleinhuis
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« Reply #1 on: February 15, 2009, 08:07:07 PM »

hmm, yummy! afro
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twinbee
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« Reply #2 on: February 16, 2009, 11:28:41 PM »

Does it taste better than normal broccoli?
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bib
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« Reply #3 on: February 17, 2009, 09:47:22 AM »

Does it taste better than normal broccoli?

They're a bit sweeter. More important, you really feel like like eating the fractal texture, it's fun  afro
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matsoljare
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« Reply #4 on: February 18, 2009, 03:48:57 PM »

Now here's a challange... can anyone manage to "reverse engineer" the Romanesco shhape into a proper 3d fractal? There's some Julia set which looks a lot like it, but it's 2d, and it would be interesting to see if someone can nail the full 3d structure!
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David Makin
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« Reply #5 on: February 18, 2009, 08:11:25 PM »

Now here's a challange... can anyone manage to "reverse engineer" the Romanesco shhape into a proper 3d fractal? There's some Julia set which looks a lot like it, but it's 2d, and it would be interesting to see if someone can nail the full 3d structure!

This is the closest I've seen:

http://geon-therealone.deviantart.com/art/Fractal-Cone-82145104
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Nahee_Enterprises
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« Reply #6 on: February 19, 2009, 10:35:25 PM »

Now here's a challange... can anyone manage to "reverse engineer" the Romanesco shhape into a proper 3d fractal?

I believe Garth Thornton created one using his program XenoDream, but at the moment I can not find the link to it.  I will see if I can locate it later on when I have a few more spare minutes.
 
« Last Edit: March 30, 2010, 01:37:57 AM by Nahee_Enterprises » Logged

Hypnogems
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« Reply #7 on: April 30, 2009, 04:04:56 AM »

Now here's a challange... can anyone manage to "reverse engineer" the Romanesco shhape into a proper 3d fractal? There's some Julia set which looks a lot like it, but it's 2d, and it would be interesting to see if someone can nail the full 3d structure!

I think this comes a little bit closer...its from Incendiascript, a new feature of Incendia 1.2.x.
Script written by program author Aexion; all I did was add color and render.

http://www.fractalforums.com/gallery/?sa=view;id=607
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Cyclops
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« Reply #8 on: August 31, 2009, 02:50:29 PM »

Food for thought eh!
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David Makin
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« Reply #9 on: October 31, 2009, 04:27:24 AM »

Found this a couple of weeks ago:

<a href="http://www.youtube.com/v/cbmQaQWyz-k&rel=1&fs=1&hd=1" target="_blank">http://www.youtube.com/v/cbmQaQWyz-k&rel=1&fs=1&hd=1</a>
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Buddhi
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« Reply #10 on: October 31, 2009, 12:28:32 PM »

Similarity is amazing!!!! the wave
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bib
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« Reply #11 on: November 06, 2009, 09:03:52 PM »

nice broccoli at 1:30 in this video
<a href="http://www.youtube.com/v/pozcRbMLBE4&rel=1&fs=1&hd=1" target="_blank">http://www.youtube.com/v/pozcRbMLBE4&rel=1&fs=1&hd=1</a>
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« Reply #12 on: November 28, 2009, 10:15:06 PM »

nice broccoli at 1:30 in this video
<a href="http://www.youtube.com/v/pozcRbMLBE4&rel=1&fs=1&hd=1" target="_blank">http://www.youtube.com/v/pozcRbMLBE4&rel=1&fs=1&hd=1</a>
Fabulous video! I'm gonna post that on facebook!
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oftakofta
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« Reply #13 on: December 28, 2009, 02:07:51 PM »

Just a quick thought experiment. If one were to take high resolution time-lapse photographs of growing Romanesco broccoli, would it be possible to calculate the in vivo growth rate of the plant cells using the best-fitting formula for mathematical Romanesco? Let us suppose we can capture detail down to the diffraction limit of optical microscopy (~0.2µm, disregard that you actually can see the cells dividing at this magnification). Alternatively, given the time-lapse growth data, could you derive a formula for the shape of Romanesco assuming 1 iteration = 1 cell division cycle?

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David Makin
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« Reply #14 on: December 28, 2009, 02:17:35 PM »

Just a bit of fun with a Juliabulb:

"Romanescu Asparagus"



If no image above then look here:

http://makinmagic.deviantart.com/art/Romanescu-Asparagus-147841840

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