Help identifying formulas

[tly]

Some years ago i tested a lot of formulas and made mostly lowreslution images (because my renderer was quite bad   )

Now im looking at some of these images and want to rerender them with higher resolution / multisampling, but i dont remember the formulas that i used...

My question is: do you think it would be possible to identify some formulas by images? I only used the standard m-set escape time method for the fractals. Ive seen similar images before, so the formulas could be well-known  

these are the images that id like to rerender:




pretty weird ones:



some variation of the burning ship:

it has henon attractor shapes as "minibrots"  

[lkmitch]

The first one looks like a rational function, maybe something like z = c(z^4-1)/z.

The second looks like a tweak to the regular Mandelbrot, maybe along the lines of z^2+c+(small number)/z.

No idea about the others.

[tly]

The first one looks like a rational function, maybe something like z = c(z^4-1)/z.

The second looks like a tweak to the regular Mandelbrot, maybe along the lines of z^2+c+(small number)/z.

No idea about the others.

Thanks, i think the rational function is a good idea, this would explain why the fractal shapes get infinitely small at the origin.

[tly]

I found the formula for the second image, its ((z^2 + 2*z + 0.1)/(2*z + 2))^2 + c 

[Imagyx]

The first one looks like a rational function, maybe something like z = c(z^4-1)/z.

The second looks like a tweak to the regular Mandelbrot, maybe along the lines of z^2+c+(small number)/z.

No idea about the others.

Nice idea, I entered your formula into my little program.Result's below 
Rational functions need to be tested further 
Thanks!

[tly]

Nice idea, I entered your formula into my little program.Result's below 
Rational functions need to be tested further 
Thanks!

nice

what startvalue did you use for z? using z = 0 obviously doesnt work, using z = c looks different in my program...

[tly]

i tried it out a bit and found, that you used the z^3 instead of z^4

[Imagyx]

Ops... I'm sorry.  
I really tried z^4 first, but it didn't look like the first one from  tly.
So I thought with functional analysis in mind to try z^3 and this one looks  more like the one which was asked for.
Well, at least there are three parts as well...I wonder why there aren't any original mandelbrots in my render but
instead some hearts  

Now there's z = c(z^4-1)/z  as well:
But as always the look depends a lot on choice of colors...