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Author Topic: Phoenix Bulb  (Read 1623 times)
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cKleinhuis
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« on: December 17, 2009, 10:05:27 PM »

the phoenix fractal rendered with triplex algebra:

z_{n+1}=z^2+cz_{n-1}

the images below are:

1. exponent = 8 phoenix triplex fractal
2. exponent = 2 phoenix triplex fractal ( the one you could resemble when compared to
3. a julia variation ( extremely interesting behaviour )
4. the classic 2d version, rendered with ultrafractal from fractint formulas


* phoenix_bulb_8.png (873.64 KB, 1023x753 - viewed 294 times.)

* phoenix_bulb_2.png (475.02 KB, 640x686 - viewed 301 times.)

* phoenix_julia2.png (317.67 KB, 640x686 - viewed 305 times.)

* phoenix_2d.png (128.48 KB, 640x480 - viewed 285 times.)
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divide and conquer - iterate and rule - chaos is No random!
BradC
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« Reply #1 on: December 17, 2009, 10:34:42 PM »

Wow, what does the back of that Julia set look like?
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cKleinhuis
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« Reply #2 on: December 17, 2009, 10:53:14 PM »

it looks from every view different wink evil alien tease

but i have found some very friendly looking fractal faces, one was lost ( gpu breakdown ) but i will post as soon as i have more

it is amazing to view the effect of the 3d triplex parameters, it seems so intuitive ...

i will ask subblue if i am allowed to publish a modified version of his script

next step will be:

add full alternation capabilities ( alternate formula + alternate seeds ) , this will be fun^10, but parameter wars !!!
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divide and conquer - iterate and rule - chaos is No random!
BradC
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« Reply #3 on: December 18, 2009, 06:15:19 AM »

I like this one, and I'm trying to implement it. How did you begin the iteration for the Mandelbrot set? To calculate the first z1, I need to know both z0 and z-1. I can't use z0=z-1=0 because then z1=0, z2=0, etc.. To begin the Julia set, did you use z0=z-1?
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cKleinhuis
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« Reply #4 on: December 18, 2009, 02:24:37 PM »

z0 is the pixel, or the 3d coordinate you want to calculate the iteration value for
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divide and conquer - iterate and rule - chaos is No random!
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