Apparently there are generalized 'Clifford algebras' that can be constructed from higher degree homogeneous polynomials. From what I can tell, these generalized 'Clifford algebras' have natural ternary, quartic, etc. operations instead of binary products.
Ordinary Clifford algebras can be made by starting with the tensor algebra over a vector space, then sculpting it down using equivalence relations made between bivectors elements of the tensor algebra and corresponding scalars of a quadratic form.
Say

is a Clifford algebra of the quadratic form

, then it has a binary product (a.k.a. the geometric product)

. The quadratic form

is used to take the squares of grade-1 elements and equate them with scalars, e.g.

, etc. This is what trims down the geometric product and keeps it closed.
So... you can actually do something similar using algebraic forms, which are a generalization of quadratic forms. A quadratic form is linked to a homogeneous quadratic polynomial. Algebraic forms are linked to
homogeneous polynomials of any degree, e.g.
cubic formsA homogeneous polynomial

of degree

in

variables, can be thought of as a function
 = 0)
. This can be used in an analogous way to generate equivalence relations such as

. I've only seen papers about ternary ones,but I think theoretically you could create an n-ary algebra analogous to a Clifford Algebra from any homogeneous polynomial.
According to
this paper, you cannot necessarily compose the ternary operation of a ternary algebra from repeated application of some binary operation. So these things are fundamentally different from the familiar binary algebras.
I'm still scratching my head on how to actually formulate these things. But it's starting to make more sense as time goes on....
One clue is
here. A symmetric tensor is the analog of a symmetric matrix, and it is decomposable in an analogous way to how symmetric matrices are diagonalizable. Wikipedia says that: "
The space of symmetric tensors of order r on a finite-dimensional vector space is naturally isomorphic to the dual of the space of homogeneous polynomials of degree r on V"... which I translate to mean that for every homogeneous polynomial of degree r on V, there is a unique symmetric tensor of order r.
Here is the scoop on decomposition of symmetric tensorsDo a search for "ternary clifford algebra" and see what you come up with. There are quite a few papers on it, though most of them are really, really hard to understand.
Obviously, I'd love to make fractals out of these things!