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jehovajah
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« Reply #15 on: September 15, 2012, 09:51:19 AM » |
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So, why is this important to know?
The Riemann Zeta function and hypothesis was used to develop a strange branching fractal, if I remember correctly. It was referenced in this forum some years ago now. How would your insight affect general fractal production, zooming and surface determination, even colour cycling?
A lot of questions I know,mbut I am in no rush . Take your time to develop your insight.
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May a trochoid of ¥h¶h iteratively entrain your Logos Response transforming into iridescent fractals of orgasmic delight and joy, with kindness, peace and gratitude at all scales within your experience. I beg of you to enrich others as you have been enriched, in vorticose pulsations of extravagance!
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hgjf2
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« Reply #16 on: June 25, 2016, 12:15:02 PM » |
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A new hint founded for to solve this the Riemann's hypothesis: I founded few formulas on sites: the relationship between the numbers of Bernoulii and the function Zeta : Z(2n)=[(-1)^(n+1)]*{[(2pi)^(2n)]/2*(2n)!}*B(2n) and Z(-n)=-[-B(n+1)]/(n+1) and the hint formula:
Z(1-s)=2[(2pi)^(-s)]*[cos(s*pi/2)]*(s-1)!*Z(s) the "holly grail".
Z(z) is the Zeta function. Z(z)=1+1/(2^z)+1/(3^z)+1/(4^z)+... when z=a+bi.
B(n) are the numbers of Bernoulli: 1;-0,5;0,1(6);0;-0,0(3);0;0,0(238095);0;-0,0(3);0;0,0(75);0;-0,2(531135);0;1,1(6);0;-7,09216...;0;54,97118...;0;
-529,1(24);0;6192,12319...;0;-86580,2(531135);0;1425517,1(6);0;-27298231,07...;0;601580873,9;0;-1511631576.7...;0;... etc.
Also the function Zeta is good helpfull for who is curious how made B(z) when z<-C\{N} where N is the lot of the natural numbers.
Also B(-1)=(pi^2)/6=1,6449340668... and B(-2)=2,40405... and B(-3)=(pi^4)/30=3.2469697011... etc.
If the Riemann's hypothesis "say" that null values for Z(z) are placed at the lines {z=a+bi|a=0} and {z=a+bi|b=1/2} at this formula
Z(1-s)=2[(2pi)^(-s)]*[cos(s*pi/2)]*(s-1)!*Z(s) if s=1/2+it then 1-s=1/2-it and 1/2=1-1/2 for any t<-R.
If I will solve the Riemann's hypothesis but and will obtain the copyright for this future big theorem, then I will publish and here at this topic this theorem.
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TheRedshiftRider
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« Reply #17 on: June 25, 2016, 12:44:10 PM » |
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Thanks for adding new information, it is nice to see people are still trying to solve it.
But please note that only one post at the time is enough if only one of the posts adds something. If there is something to add to the post afterwards or you think you've forgotten something please just edit your post instead of posting a new one.
The second post has been removed because it did not add anything. If you have questions about this please send me a personal message.
Edit: Well, actually you should contact Sockratease. He was a little faster. Maybe a bit too fast?
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Motivation is like a salt, once it has been dissolved it can react with things it comes into contact with to form something interesting.  |
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TheRedshiftRider
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« Reply #18 on: July 14, 2016, 06:08:12 PM » |
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Shouldn't you contact a mathematical institute about this? It could help to the whole process of solving this theorem.
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Motivation is like a salt, once it has been dissolved it can react with things it comes into contact with to form something interesting. |
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hgjf2
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« Reply #19 on: July 16, 2016, 08:52:11 AM » |
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I was tried to contact one math institute, but sadly in Romania don't exist functionally math institute. The self research institute in sciences will be only this at Magurele whick studying lasers.
Also not only Riemann hypothesis awaiting to be theorem, that I'm discovered a new theorem about the holomorphy in R^n with n>2 whick awaits to been published and presented proper, also I contacted the math society at University of Bucharest , named "Gazeta Matematica" , but if I want to gain copyright for my discoveries, I must be carefull that those discoveries to not been takes by otherwise, also I search an editure for to can publishing those how demanding the office of trademarks, because only an editure will representing me in instance.
The university "Spiru-Haret" where I graduated the master and the faculty of maths, don't have math society like "Gazeta Matematica"
I still working at presentation, and ensuring that theories don't have lags.
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zebastian
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« Reply #20 on: July 16, 2016, 03:57:34 PM » |
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hi hgjf2, when you got your paper ready you can upload it to arxiv.org to claim your copyright and make it public. I think you are getting fast feedback for dealing with the riemann zeta function.  Be sure your theory is bullet proof. Has someone else of you had contact with arxiv.org as a publication platform? |
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hermann
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« Reply #21 on: October 02, 2016, 01:47:43 PM » |
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Did you know, that one can post LaTex formulars here in fractal forums?  = \sum_{n=1}^\infty {\frac {1} {n^s}} = 1 + \frac{1}{2^s} + \frac{1}{3^s} + \frac{1}{4^s} + \frac{1}{5^s} + \ldots)  = \prod_{p \in \mathbb{P}} {\left( 1-p^{-s} \right)}^{-1} = \prod_{p \in \mathbb{P}} {\frac{1}{1-\frac{1}{p^{s}}}} = \frac{1}{(1-\frac{1}{2^{s}}) (1-\frac{1}{3^{s}})(1-\frac{1}{5^{s}}) (1-\frac{1}{7^{s}}) \ldots})  = 2^{s}\pi^{s-1}\sin \left(\frac{\pi s}{2} \right) \Gamma(1-s)\zeta(1-s)) } \Gamma\left(\frac{s}{2} \right)\zeta(s)=\pi^{-\left(\frac{1-s}{2} \right)}\Gamma\left(\frac{1-s}{2}\right)\zeta(1-s)) May be this will help you to make expressions more readable. Hermann |
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hermann
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« Reply #23 on: October 10, 2016, 04:33:13 PM » |
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I you realy have a proofs for Riemann's Hypothesis you will be a rich man! If you have 10% for me it will help me for an early retirement. Hermann
<![CDATA[<a href="https://www.youtube.com/v/rGo2hsoJSbo&rel=1&fs=1&hd=1" target="_blank">https://www.youtube.com/v/rGo2hsoJSbo&rel=1&fs=1&hd=1</a>]]>P.S There is a misspelling in the title it should be Riemann H ypothes is |
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TheRedshiftRider
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« Reply #24 on: October 10, 2016, 06:36:10 PM » |
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I you realy have a proofs for Riemann's Hypothesis you will be a rich man!
If you have 10% for me it will help me for an early retirement.
That would be nice. Maybe the forum itself could use some of it as well I suppose, to expand a little.  Edit: thank you for sharing that video. I really needed a refresher. |
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« Last Edit: October 10, 2016, 09:12:24 PM by TheRedshiftRider »
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Motivation is like a salt, once it has been dissolved it can react with things it comes into contact with to form something interesting. |
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hermann
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« Reply #25 on: October 20, 2016, 09:37:31 PM » |
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Another nice video on Riemann's Hypothesis.
<![CDATA[<a href="https://www.youtube.com/v/VTveQ1ndH1c&rel=1&fs=1&hd=1" target="_blank">https://www.youtube.com/v/VTveQ1ndH1c&rel=1&fs=1&hd=1</a>]]> |
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