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Author Topic: An Icosikaitrigon  (Read 1093 times)
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thom
Fractal Bachius
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« on: May 30, 2012, 04:50:25 AM »

An Icosikaitrigon



http://www.fractalforums.com/index.php?action=gallery;sa=view;id=11580


  The polygon(shape) is called an icosikaitrigon.  The background is the Orion Nebula photographed by the Hubble Space Telescope.  It required 105 rotations to make the photograph.
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DarkBeam
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Fragments of the fractal -like the tip of it


« Reply #1 on: May 30, 2012, 11:57:41 AM »

I preferred when you called your pics "thomz". hrmm

 rolling on floor laughing jokeee
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No sweat, guardian of wisdom!
thom
Fractal Bachius
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« Reply #2 on: May 30, 2012, 01:11:07 PM »

  I have to agree...but how many time do you get to use words that are worth 37 points in Scrabble even without a coloured tile?

thomz
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Alef
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WWW
« Reply #3 on: May 30, 2012, 07:53:51 PM »

Did you mean: Icosikaitetragon   cheesy
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fractal catalisator
Dinkydau
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WWW
« Reply #4 on: May 30, 2012, 10:45:22 PM »

nice
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thom
Fractal Bachius
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« Reply #5 on: May 30, 2012, 11:23:52 PM »

   20  icosagon
   21  icosikaihenagon, icosihenagon
   22  icosikaidigon
   23  icosikaitrigon
   24  icosikaitetragon
   25  icosikaipentagon
   26  icosikaihexagon
   27  icosikaiheptagon
   28  icosikaioctagon
   29  icosikaienneagon
   30  triacontagon
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Pauldelbrot
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pderbyshire2
« Reply #6 on: May 31, 2012, 12:34:37 AM »

   20  icosagon
   21  icosikaihenagon, icosihenagon
   22  icosikaidigon
   23  icosikaitrigon
   24  icosikaitetragon
   25  icosikaipentagon
   26  icosikaihexagon
   27  icosikaiheptagon
   28  icosikaioctagon
   29  icosikaienneagon
   30  triacontagon

And, of course, in three dimensions the -gon ending should become -hedron.

Then again, I'm not sure how well the rest applies here either. The basic shape appears to be an icosahedron. If you count the flattened-off edges, that adds thirty* more sides, making it a pentacontahedron. If you count the triangular facets being indented like they are, each counts triple, adding another forty net sides for an enneacontahedron. If you count all the additional fractal bevels ... er ... what's the Greek word for infinity? wink

* Note that each of the twenty triangular facets borders three halves of flattened-off edges. There are therefore 20*3/2 = 30 full flattened-off edges.
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Pauldelbrot
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pderbyshire2
« Reply #7 on: May 31, 2012, 12:37:20 AM »

On the other hand, counting only the sides facing the camera and including the flattened-off edges, but not the indented triangles, I do count 23 faces ... hmm. smiley
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thom
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« Reply #8 on: May 31, 2012, 12:52:46 AM »

Well...to begin with is was supposed to be a simple globe...but you know how things get out of hand!
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