Inverse Mandelbrot

[makc]

I was thinking, it must be possible to reverse the formula z(k+1) = z(k)^2 + c to z(k) = sqrt (z(k+1) - c), run k downwards, change bailout condition from r > 2 to r < 2 and still get same Mandelbrot. However, when I try this, I get only two major features plus some weird shape in re>0 area. Why is that?

[makc]

I get only two major features plus some weird shape in re>0 area.

Never mind two major features, they were due to the code to explicitly skip them; that shape in re>0 area is all there is to it.

[hobold]

How do you know which k to start with? And which z(k)?

[makc]

How do you know which k to start with? And which z(k)?

ah, you're right, I've been starting from c.

[aluminumstudios]

If it were possible to run backwards, Buddhabrot's would be a heck of a lot easier to render!

[kram1032]

not bad actually.
If the upper half is "true", you could just mirror it to get the whole set...

However isn't that up down the imaginary direction?
So, the strange shape is at Im<0, rather than Re>0?

(Or did I oversee something?)

[makc]

nah up side is normal mandelbrot to compare it easier.

here is how it looks. I actually wrote that to extend the orbits into the past, and then I spontaneously cam up with idea to render fractal itself using that code.

[matsoljare]

The problem is that for the complex squaring formula, there are two different numbers that give the same result, so you can't know for sure which one of them is the correct "step backwards". For the power of three, there are three different roots, and so on.....

[kram1032]

isn't it rather that BOTH are correct in that case?