DarkBeam
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Fractal Senior
Posts: 2512
Fragments of the fractal -like the tip of it
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« Reply #15 on: January 09, 2017, 11:51:47 AM » |
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Dear Jos mb3d has a very limited number of sliders. I had to use a binary encoding of all your options in order of effect beauty Option 1 enables your "Four generators". Option 2 DISables "Show balls". (hmm... should be?) 4 for sphere inversion. To enable several options sum the numbers: 3 enables 4 gen and show balls and zero disables all
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No sweat, guardian of wisdom!
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Sabine
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« Reply #16 on: January 09, 2017, 12:28:19 PM » |
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@Luca Can you add this text about the options to the description? It would be so helpful!
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sabine62.deviantart.com
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Aexion
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« Reply #17 on: January 09, 2017, 02:37:28 PM » |
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To Sabine and KRAFTWERK: Many Thanks!! To Aexion post codeeeeeeeeeeee I forgot to post the .frag! my apologies! Consider this .frag as a non canonical, mutant version of the original version. Its some experiments that I was trying to do. It basically add a Julia set (and a multiplier) and two possible entry points for the abs() function. All is under the Jul section, and you can see the examples (variations of the original examples) in the Jul presets. One example is missing, the first picture, that was done by changing the Julia function by the burning ship formula, but I didn't wanted to burden the .frag with more conditionals!. Anyways, I will try other functions!
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| Fractals all the way.. Incendia for 3D Fractals Aural for Musical Fractals |
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bib
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« Reply #18 on: January 09, 2017, 05:10:19 PM » |
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Dear Jos mb3d has a very limited number of sliders. I had to use a binary encoding of all your options in order of effect beauty Option 1 enables your "Four generators". Option 2 DISables "Show balls". (hmm... should be?) 4 for sphere inversion. To enable several options sum the numbers: 3 enables 4 gen and show balls and zero disables all It took me discussions on deviantart with some core protagonists to realize that the answer to my question "how to combine options 2 and 4?" was simply "option 6"
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Between order and disorder reigns a delicious moment. (Paul Valéry)
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Tim Emit
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« Reply #19 on: January 09, 2017, 07:11:41 PM » |
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@ Aexion and all.. thanks for the fragment ..very nice .. keep up the good work
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Sabine
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« Reply #20 on: January 10, 2017, 01:46:42 PM » |
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@Aexion Thank you for adding the Julia and posting the .frag, so much fun to play with! Seems whatever you do to it, it throws up goodies:)
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sabine62.deviantart.com
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pupukuusikko
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« Reply #21 on: January 10, 2017, 09:11:17 PM » |
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Here's a possibly interesting mod, found after intensive frobbling I replaced the warping function with boxfold and removed the separation line thing. Surprisingly, resulting fractal still has nice kleinian style spirals, although they are arranged unnecessarily symmetrically, and shiny spheres are gone. On a positive side, the thing does not seem to have cuts. Frag is attached below. examples:
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« Last Edit: January 10, 2017, 09:36:48 PM by pupukuusikko, Reason: added third image »
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DarkBeam
Global Moderator
Fractal Senior
Posts: 2512
Fragments of the fractal -like the tip of it
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« Reply #22 on: January 10, 2017, 10:46:49 PM » |
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No sweat, guardian of wisdom!
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pupukuusikko
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« Reply #23 on: January 10, 2017, 10:58:22 PM » |
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Take your time Luca, people wil be happy with the vanilla version for weeks (although it IS a great formula!)
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Sabine
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« Reply #24 on: January 11, 2017, 12:37:36 AM » |
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I Do need some sleep once in a while, you know? Thanks for posting the .frag, Pupukuusikko!
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sabine62.deviantart.com
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JosLeys
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« Reply #25 on: January 11, 2017, 11:34:42 AM » |
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Using a boxfold makes things go a little wild! Two images below in the 'standard' view. The first is the normal situation, the second is with a boxfold in the three direction, no separation line, and so applying always the same transformation.
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DarkBeam
Global Moderator
Fractal Senior
Posts: 2512
Fragments of the fractal -like the tip of it
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« Reply #26 on: January 11, 2017, 08:01:25 PM » |
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yaaaaaaaay I figured out how to show hexagon flakes instead of plain "squares", the result is stunning especially if coupled with aexionj: (replace wrap with) (edit: storeint equals a FLOOR, not roundint) x += bdiva*y; x -= -bsx; z -= -bsz; int bop = (storeint(z/bsz2) ); // HEXAGON MOD MiscOps = (loadNthIntVar(2,6*szof1dbl))&8; // HEXAGON MOD enabled? yes/no if (MiscOps) { if (bop&1) x-= bsz; // HEXAGON MOD } x += -bsx-bsx2*storeint(x/bsx2); z += -bsz-bsz2*bop; MiscOps = (loadNthIntVar(2,6*szof1dbl))&1; // 3d mode if (MiscOps) { y += -a*(storeint(y/a)); } x -= bdiva*y; edit; too bad the method is adding some cuts around
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No sweat, guardian of wisdom!
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pupukuusikko
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« Reply #27 on: January 11, 2017, 08:20:30 PM » |
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Using a boxfold makes things go a little wild! Two images below in the 'standard' view. The first is the normal situation, the second is with a boxfold in the three direction, no separation line, and so applying always the same transformation.
I very much appreciate your interest, nice comparison, it is a little on the wild side However, the boxfold is not to blame, if you use boxfold with the separation line, it is almost identical to the original, except for different symmetries. This combination also produces cuts in the same way as the original formula. In my script you get comparable results by setting fold multiplier = 1 instead of 0.5. Below a comparison, left is the original wrapping and right is boxfold.
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JosLeys
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« Reply #28 on: January 11, 2017, 08:32:31 PM » |
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@pupukuusikko I cannot run your frag file, it crashes my computer. I tried to replicate what you did in another frag file but probably made some mistakes.
I probably have an ancient version of Fragmentarium. What version are you using and where can I find it?
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pupukuusikko
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« Reply #29 on: January 11, 2017, 09:13:04 PM » |
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@josLeys: Sorry to hear that. I also use old version, 1.0.0, from http://syntopia.github.io/Fragmentarium/You could try uncommenting the fast-raytracer.frag and commenting the DE-Kn2.frag to speed it up, also set "Lock-to 1/2 window size' or lower. These could help with the gpu-related crashes, which I've experienced too. That said, your results for boxfold+no separation look exactly like mine, so I'm sure your frag is good.
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