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Author Topic: 3D trigonometry help  (Read 1004 times)
Description: I will say that I have not the time for figuring it out, but is not true
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fractower
Iterator
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Posts: 173


« Reply #15 on: February 22, 2012, 05:29:23 AM »

I reversed the identities in my original post. They should have been  (|X cross M| = XM sin(ang)) and (X dot M = XM cos(ang)). You want to use the dot product version since it gives an unambiguous result between 0 and pi (0 and 180).

ang = acos ((X dot M)/XM)  where XM is actually |X||M|.

Since X is known in advance, you can set its length to 1 when you start.
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Kali
Fractal Supremo
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Posts: 1138


« Reply #16 on: February 22, 2012, 07:03:31 AM »

Ok, I did it, and if I did it right, the results are dissapointing  sad

Mandelbrot is a flat wheel, as hobold expected, and julias are something like quaternions, only worse.
It's not worth posting pictures  embarrass 
Also the DE is not working very good with this, too much noise!

So the quest continues... thanks anyway for your help, guys  wink
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DarkBeam
Global Moderator
Fractal Senior
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Posts: 2512


Fragments of the fractal -like the tip of it


« Reply #17 on: February 22, 2012, 09:37:16 AM »

Ok, I did it, and if I did it right, the results are dissapointing  sad

Mandelbrot is a flat wheel, as hobold expected, and julias are something like quaternions, only worse.
It's not worth posting pictures  embarrass 
Also the DE is not working very good with this, too much noise!

So the quest continues... thanks anyway for your help, guys  wink

To do the de you must derive your functions, don't ask me how... that's why I never used Fragmentarium cheesy
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No sweat, guardian of wisdom!
DarkBeam
Global Moderator
Fractal Senior
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Posts: 2512


Fragments of the fractal -like the tip of it


« Reply #18 on: February 22, 2012, 04:33:22 PM »

And this page comes handy I guess:

http://en.wikipedia.org/wiki/Trigonometric_identity
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No sweat, guardian of wisdom!
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