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Author Topic: Buddhabrot R&D Gallery  (Read 3963 times)
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richardrosenman
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« Reply #30 on: August 19, 2010, 06:41:56 PM »

I'm aware of that wink
http://kram1032.deviantart.com/gallery/#Fractals <- there. TONS of different formulas, using the buddhabrot technique to render them.
I'm currently working on an other one smiley

Kram1032, there's some really nice renders there! Congrats!

-Richard
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kram1032
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« Reply #31 on: August 19, 2010, 07:13:20 PM »

thanks smiley
You still didn't experiment with z*tanz, did you?
It looks really nice.
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richardrosenman
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« Reply #32 on: August 19, 2010, 07:21:51 PM »

thanks smiley
You still didn't experiment with z*tanz, did you?
It looks really nice.

I'd love to but I'm not sure I can with my algorithm and the way it's set up. If you take a look at this post: http://www.fractalforums.com/gallery-b179/buddhabrot-creative-gallery/msg20368/#msg20368 You'll see that you mentioned I can't do a Tan variation. No?

-Richard
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richardrosenman
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« Reply #33 on: August 22, 2010, 05:26:35 AM »

Some more tests, this time mutating c.x and c.y:



-Richard
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richardrosenman
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« Reply #34 on: August 22, 2010, 05:27:08 AM »



-Richard
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richardrosenman
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« Reply #35 on: August 22, 2010, 05:28:09 AM »



-Richard
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kram1032
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« Reply #36 on: August 22, 2010, 11:07:55 PM »

you can't do a tan variant based on the simple parameters you had there. That's all I meant with you can't do it directly. However, it's straight forward to change it into one.
As you programmed that software on your own, it should be straight forward to change the source wink

All you need to do is to change your equations which do complex squaring into equations which do complex tan times a complex number:

instead of

x->x²-y²+x0
y->2xy+y0

do

x->(x*sin(2x)-y*sinh(2y))/(cos(2x)+cosh(2y))+x0
y->(y*sin(2x)+x*sinh(2y))/(cos(2x)+cosh(2y))+y0

Btw the new stuff is very nice again smiley
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