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Author Topic: attempt on triplex numbers over exponential form  (Read 3279 times)
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kram1032
Fractal Senior
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Posts: 1863


« on: December 09, 2009, 10:21:48 PM »

Here is the idea:

complex numbers have this exponential form:

z = r*exp(1*\phi*i) or z=r*(cos(\phi)+sin(\phi))
where 1 is the positive unit 1-vector (which is trivial of course smiley )
quaternions have this form:

z = r*exp(\phi*v)
where
v=a*i+b*j+c*k
and
a,b,c are forming a unit 3-vector.

or
z=r*(cos(\phi)+a*i*sin(\phi)+b*j*sin(\phi)+c*k*sin(\phi))

so, here's the idea on how to do extensions:

basically, take a unit 2-vector, that is, cos(angle) and sin(angle) (as sin²x+cos²x=1)
this way, I propose the exponential notation to be:

z=r*exp(\phi*(i*cos(\theta)+j*sin(\theta)))

or
<br />z=r*(cos(\phi)+i*sin(\phi)*cos(\theta)+j*sin(\phi)*sin(\theta))

note that this also is consistent with how spherical coordinates might be defined smiley

(spherical to cartesian -> [r*cos(\phi),r*sin(\phi)*cos(\theta),r*sin(\phi)*sin(\theta)])

this would allow for relatively simple power rules (at *least* for integer powers)

power n:

r^n*exp(n*\phi*(i*cos(\theta)+j*sin(\theta)))

and this is where I am right now.

This, if developed further, is one of two things: - either it's the best representation for triplex numbers, I personally could think of, or it's just an other way to produce boring Mandelbrot-rotations-around-real-axis....
(or actually, maybe it's both)

either way, this could be interesting....
can anyone out there help me further on this? smiley

for example, if I did it right, then it's kind of clear now how \phi transforms with powers, but I can't yet directly see, what \theta does...
« Last Edit: December 10, 2009, 01:26:48 AM by kram1032 » Logged
kram1032
Fractal Senior
******
Posts: 1863


« Reply #1 on: December 10, 2009, 01:42:16 AM »

I think I need to understand powers of quaternions better.
Particularily how the a,b,c values change seperately from the angle alpha in exponential form...
else I wont get to the actual Mandelbulb formula to be derived from this idea.

For now, and I guess that would be wrong, this would be the iteration formula, obviously being way too simple..

r -> r^n

phi -> n*phi

theta -> theta

though, was this actually tried yet? I doubt the result would be tooooo interesting but I'd like to see it anyway...
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bugman
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Posts: 122



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« Reply #2 on: December 10, 2009, 06:55:41 PM »

I posted an exponential triplex formula here:
http://www.fractalforums.com/theory/triplex-algebra/msg9554/#msg9554
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