Logo by MandelBRO - Contribute your own Logo!

END OF AN ERA, FRACTALFORUMS.COM IS CONTINUED ON FRACTALFORUMS.ORG

it was a great time but no longer maintainable by c.Kleinhuis contact him for any data retrieval,
thanks and see you perhaps in 10 years again

this forum will stay online for reference
News: Did you know ? you can use LaTex inside Postings on fractalforums.com!
 
*
Welcome, Guest. Please login or register. January 13, 2026, 05:13:11 PM


Login with username, password and session length


The All New FractalForums is now in Public Beta Testing! Visit FractalForums.org and check it out!


Pages: [1]   Go Down
  Print  
Share this topic on DiggShare this topic on FacebookShare this topic on GoogleShare this topic on RedditShare this topic on StumbleUponShare this topic on Twitter
Author Topic: Embossed Spirals  (Read 1112 times)
0 Members and 1 Guest are viewing this topic.
Pauldelbrot
Fractal Senior
******
Posts: 2592



pderbyshire2
« on: September 09, 2011, 03:05:59 AM »

Embossed Spirals



http://www.fractalforums.com/index.php?action=gallery;sa=view;id=8444

A familiar Seahorse Valley Mandelbrot with an unusual coloring: the "grad" of the smoothed iterations. Black = the smoothed iteration value increases in the positive real direction, violet = positive imaginary, white = negative real, pinkish = negative imaginary.

This coloring method, when used with a cyclic gradient with strong luminance contrast, produces an embossed, three-dimensional look.

A second layer with normal smoothed iterations darkens the seahorse cores and turns the edge of the minibrot yellow-brown.

Mathematically, the calculations resemble those for distance estimator. The derivative dzn/dc is maintained, starting as 0 (since z0 = 0 is a constant independent of c) and being updated by new-der = 2 times old-der, times zn, plus 1. So far, so identical to distance estimator.

The difference is in what's done at the end of the iteration. For distance estimator, the modulus of the escaped z is multiplied by its own logarithm and by half, and divided by the modulus of the derivative. For this, I multiply the escaped z (not its modulus) by half and divide by the derivative (not its modulus), leaving the logarithmic term of the product out entirely and yielding a complex number. That's the grad. It's the argument of this complex number that is used for the coloring: the direction of the gradient.
« Last Edit: September 09, 2011, 06:58:49 AM by Pauldelbrot » Logged

Pages: [1]   Go Down
  Print  
 
Jump to:  

Related Topics
Subject Started by Replies Views Last post
Embossed Koch Snowflake Images Showcase (Rate My Fractal) Ross Hilbert 0 3721 Last post November 03, 2008, 02:26:23 PM
by Ross Hilbert
Embossed Star Images Showcase (Rate My Fractal) Pauldelbrot 0 1207 Last post July 30, 2011, 05:16:14 AM
by Pauldelbrot
Spirals Again Mandelbulb3D Gallery trafassel 0 1420 Last post January 14, 2012, 04:44:52 PM
by trafassel
Ducks embossed Images Showcase (Rate My Fractal) DarkBeam 6 1253 Last post February 21, 2012, 04:02:22 PM
by DarkBeam
Embossed Images Showcase (Rate My Fractal) 1Bryan1 2 959 Last post November 30, 2015, 06:08:46 AM
by 1Bryan1

Powered by MySQL Powered by PHP Powered by SMF 1.1.21 | SMF © 2015, Simple Machines

Valid XHTML 1.0! Valid CSS! Dilber MC Theme by HarzeM
Page created in 0.227 seconds with 27 queries. (Pretty URLs adds 0.01s, 2q)