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Author Topic: Semi-Conformal tetrahedral pow 3?  (Read 391 times)
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DarkBeam
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« on: December 30, 2016, 11:36:17 AM »

Question to Tglad  angel
Can you kindly provide us the power 3 variant (and/or general int power) of your nice formula? I tried but I am not really satisfied with my result, please heeelp  cry
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M Benesi
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« Reply #1 on: December 30, 2016, 09:54:05 PM »

What's the original formula?
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DarkBeam
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« Reply #2 on: December 30, 2016, 11:02:52 PM »

Matthew you are welcome to try. But it is kind of complicated

http://www.fractalforums.com/index.php?topic=20778.msg80517#msg80517
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Tglad
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« Reply #3 on: January 01, 2017, 01:37:00 AM »

Hi darkbeam, I think the answer is that there is no power 3. In fact it's probably only referred to as power 2 as it is similar to the Mandelbulb power 2 (and even that is only loosely linked to actual powers on fields such as on complex numbers).
But 'power' 4, 8 etc are possible by just repeating the transform.
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DarkBeam
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« Reply #4 on: January 01, 2017, 09:30:43 AM »

Sorry if I insist but I saw those images: http://www.fractalforums.com/the-3d-mandelbulb/a-new-3d-mandelbrot-like-fractal/msg9947/#msg9947

It was pretty! smiley
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Tglad
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« Reply #5 on: January 01, 2017, 11:31:59 AM »

Hey, maybe it is possible then... or maybe I meant power 4... you could try doing the power 2 operation twice and see if it looks like those pictures.
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DarkBeam
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Fragments of the fractal -like the tip of it


« Reply #6 on: January 01, 2017, 02:46:09 PM »

I have tried but maybe I will try again soon grin
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M Benesi
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« Reply #7 on: January 03, 2017, 03:25:14 AM »

Thx.  cheesy
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