Logo by Pauldelbrot - Contribute your own Logo!

END OF AN ERA, FRACTALFORUMS.COM IS CONTINUED ON FRACTALFORUMS.ORG

it was a great time but no longer maintainable by c.Kleinhuis contact him for any data retrieval,
thanks and see you perhaps in 10 years again

this forum will stay online for reference
News: Did you know ? you can use LaTex inside Postings on fractalforums.com!
 
*
Welcome, Guest. Please login or register. April 20, 2024, 04:20:15 AM


Login with username, password and session length


The All New FractalForums is now in Public Beta Testing! Visit FractalForums.org and check it out!


Pages: [1]   Go Down
  Print  
Share this topic on DiggShare this topic on FacebookShare this topic on GoogleShare this topic on RedditShare this topic on StumbleUponShare this topic on Twitter
Author Topic: Julia Set that looks like a Mandelbrot Set  (Read 4550 times)
Description: Julia Set that looks like a Mandelbrot Set
0 Members and 1 Guest are viewing this topic.
bugman
Conqueror
*******
Posts: 122



WWW
« on: November 03, 2009, 07:34:44 PM »

This Julia set was created using the Modified Inverse Iteration Method (MIIM) for the formula z=z(z+1.2)².
I think it bears a remarkable resemblance to the Mandelbrot set. Which gets me thinking, I wonder if is there exists a formula for a Julia set that is exactly the same as the standard Mandelbrot set? If so, I imagine that would be a noteworthy identity for mathematicians. And it would open up the doors for creating inverse Mandelbrot sets (and possibly inverse 3D Mandelbrot sets!).


* Julia Set that looks like a Mandelbrot Set.jpg (13.54 KB, 276x276 - viewed 948 times.)
« Last Edit: November 03, 2009, 09:15:01 PM by bugman » Logged
Dinkydau
Fractal Senior
******
Posts: 1616



WWW
« Reply #1 on: November 06, 2009, 02:06:05 PM »

Isn't the mandelbrot set actually a Julia set?
Logged

lkmitch
Fractal Lover
**
Posts: 238



« Reply #2 on: November 06, 2009, 03:48:02 PM »

Isn't the mandelbrot set actually a Julia set?

No--for an iterated formula of the form z = f(z; c), a Julia set is a set of initial z values, whereas a Mandelbrot set is a set of c values.
Logged
David Makin
Global Moderator
Fractal Senior
******
Posts: 2286



Makin' Magic Fractals
WWW
« Reply #3 on: November 06, 2009, 08:37:36 PM »

Isn't the mandelbrot set actually a Julia set?

No--for an iterated formula of the form z = f(z; c), a Julia set is a set of initial z values, whereas a Mandelbrot set is a set of c values.

To put it another way - a Mandelbrot is a view of many different functions each with the same start value and a Julia is a view of a single function with many different start values.
Logged

The meaning and purpose of life is to give life purpose and meaning.

http://www.fractalgallery.co.uk/
"Makin' Magic Music" on Jango
Pages: [1]   Go Down
  Print  
 
Jump to:  

Related Topics
Subject Started by Replies Views Last post
Mandelbrot Maps: An open-source Mandelbrot/Julia explorer for Android Smartphones / Mobile Devices withad 0 10066 Last post March 20, 2012, 07:35:07 PM
by withad
Spacefilling Julia and Mandelbrot Fractals (new) Theories & Research Pauldelbrot 6 820 Last post June 18, 2013, 12:25:23 PM
by Pauldelbrot
Mandelbrot/Julia hybrids part 1 Images Showcase (Rate My Fractal) phtolo 3 2228 Last post November 22, 2013, 11:25:53 PM
by cKleinhuis
Mandelbrot/Julia hybrids part 2 Images Showcase (Rate My Fractal) phtolo 0 833 Last post November 23, 2013, 11:49:14 AM
by phtolo

Powered by MySQL Powered by PHP Powered by SMF 1.1.21 | SMF © 2015, Simple Machines

Valid XHTML 1.0! Valid CSS! Dilber MC Theme by HarzeM
Page created in 0.13 seconds with 24 queries. (Pretty URLs adds 0.006s, 2q)