Title: Negative dimensions of time-like curves Post by: Tglad on August 23, 2017, 03:18:51 AM Time-like curves are points following a trajectory.
I realised they are different from spatial curves because their dimension can be negative. We have to use the Einstein version of space-time (in fact Minkowski space-time), rather than Newton's for this to work. In this space-time a square distance (or period) in time is negative, whereas is it positive for a square distance in space. Consequently the proper time period of a trajectory (the time experience by the moving point) actually gets smaller as you add more iterations, if this happens quickly enough you can get negative dimensions: (https://1.bp.blogspot.com/-GZ0S-hO80O8/WZWDTjt9ykI/AAAAAAAABeA/xOCg_5sfBIo01OCziraBMTNd6FTbH6fXQCLcBGAs/s640/negative_dims.png) This curve is the sibling of the Von Koch curve and the Weiserstrauss function. They differ by having one dimension who's square is negative, positive and zero respectively. The smaller dimension trajectories look like they have no structure but that is because the point is travelling close to the speed of light so we can't see the bends and curves. If we animated the future trajectory depicted from the point's perspective, I think you could see a lot of twists and turns. If the point is moving in two spatial dimensions we can get a different modification of the Von Koch curve in the two spatial dimensions this time: (https://3.bp.blogspot.com/-8mEtdGfaLdI/WZV_gsFz2lI/AAAAAAAABd0/35BMylWM9vEUw8CGWnK9C5QwK0y1f0TTgCLcBGAs/s640/scattering.png) As the dimension tends to 2, the shape tends to a smaller and smaller 90 degree Koch curve (solid diamond), as it tends towards -infinity the shape tends to a single vertical reflection. But it is worth stressing that this is not a shape, it is the trajectory of a point going at light-speed, in fact it is the motion of a photon, so it is a bit like the internal scattering process when light reflects off something. Title: Re: Negative dimensions of time-like curves Post by: Chillheimer on August 23, 2017, 11:37:51 AM very interesting.
but I only understand half of this, because I'm missing some background knowledge. I hope you don't mind clearing things up a bit (if this goes too deep for a post, just say so too) what exactly is travelling through space time and creating those curves you draw here? does each curve represent a photon ? what formula do you use to create these curves? "ingoing/outgoing light" internal in what? hm. all I can say that this resonates heavily with some if my intuitional findings of parallels between buddhabrot-trajectories and "behaviour of particles and patterns in our reality". I need to go through my notes to find it. Sadly I miss the mathematical background that would enable me to articulate this better.. Title: Re: Negative dimensions of time-like curves Post by: Tglad on August 24, 2017, 01:54:02 AM This diagram is helpful...
When you rotate a spatial axis y towards another spatial axis x, the vertical component decreases (it rotates down). When the vertical axis is time the equivalent of rotating is changing speed. According to Newton when you change speed the vertical component doesn't change. But in fact (and according to Einstein) when you change speed the vertical component increases. This is precisely the reason when a Koch curve gets longer in each iteration, the Wieserstrauss function time period stays the same, and my time-like curve's proper time decreases each iteration. This is why spatial fractals increase in dimension with roughness, but spatio-temporal fractals decrease in dimension with roughness (using Eintein / Minkowski space), or don't change dimension with increasing roughness if using Newton's space-time. Quote what exactly is travelling through space time and creating those curves you draw here? I think it is a photon. The fractal gets closer and closer to light-speed each iteration. So the exact fractal is either light-speed or infinitely close to light speed. So we can think of it as a single photon bouncing around along the shown paths. Quote what formula do you use to create these curves? It is basically a Koch curve formula but the constant bend angle is replaced with a constant Lorentz boost angle in the 1+1D case. Note that in space-time you don't write 2D as temporal dimensions are different to spatial ones as you see in the diagram, so you write 1+1D, or for the real world it is 3+1D. Meaning 3D spatially and 1 time dimension. Title: Re: Negative dimensions of time-like curves Post by: Tglad on August 25, 2017, 02:32:47 AM Here's the 1+1D equivalent of the Levy C curve in 2D and the Blancmange fractal:
(https://1.bp.blogspot.com/-JpHYAI-qY_Y/WZ6oOkqOydI/AAAAAAAABh4/UTbLoPPglLA18xSsYHefsSlyWxaM_gnFwCLcBGAs/s320/levyneg1D.png) and the 2+1D version: (https://4.bp.blogspot.com/-pylcBH-WT40/WZ6ogMNyfvI/AAAAAAAABh8/267pgxrA7r0KrSeOpBHd7vAGMfTyZJOQgCLcBGAs/s480/levyneg.png) The 0D trajectory looks a lot like two circular arcs. All these curves have boost symmetry, which means that you can go at all sorts of different velocities and you will see the same trajectory relative to you, at least for some small part. Title: Re: Negative dimensions of time-like curves Post by: Tglad on August 30, 2017, 05:10:29 AM and here's a final example, which is everywhere C(1) smooth spatially, despite having a fractional timelike dimension:
(https://2.bp.blogspot.com/-d17D2wBd_Xs/WaYrNwQ0iNI/AAAAAAAABic/rDRHSPM_iIEXxiJWcUGdyANSLzranwGiACLcBGAs/s960/blob%2B-%2BCopy.png) (by a+bD I mean its spacelike extents are aD and its temporal extents (measuring proper time) are bD). Title: Re: Negative dimensions of time-like curves Post by: Alef on August 31, 2017, 11:43:44 AM Any hints at faster than light travel or time machine?
Title: Re: Negative dimensions of time-like curves Post by: Khashishi on September 06, 2017, 11:49:12 PM What definition of dimension are you using? I don't see how you define a negative Hausdorff dimension or a negative Minkowski dimension.
Negative interval doesn't necessarily mean a negative dimension. Since a light ray has zero interval, it can be covered by a ball of radius 0, so the dimension should be 0. But you say it's -1? Title: Re: Negative dimensions of time-like curves Post by: Tglad on September 07, 2017, 01:26:46 PM Good question, it's the Hausdorff dimension. There are several equivalent definitions but for a fractal where you replace one line with n lines at 1/s the scale, you get D=log(n)/log(s), so for a Koch curve you get log(4)/log(3) which is about 1.26. For spatial fractals s is always less than n, for time-like curves the equivalent of the length of a line is the proper time period, and s is always more than n. Yes, I consider a light ray to be 0D, no (proper) time passes for a photon. The confusing part is that in the first diagram in this topic the curve seems to approach a light-like ray as the dimension goes to -1, in fact it doesn't stop at -1D, it appears to get closer as the dimension goes all the way to minus infinity. But even though it looks close to the shape of the green light ray it isn't really, it is just hard to distinguish shape at high velocities unless you yourself travel close to that velocity (so perform a boost transform). |