Welcome to Fractal Forums

Fractal Math, Chaos Theory & Research => General Discussion => Topic started by: Chillheimer on August 31, 2016, 12:27:55 AM




Title: Do z-->z/c² or z-->z*c² create a fractal
Post by: Chillheimer on August 31, 2016, 12:27:55 AM
Hi guys!
I am wondering if either z-->z/c²  or z-->z*c² will form anything fractal if fed with the right starting values.
And what happens if I set c to a fixed value and just change z?

I have no clue how I could check any of this or where to start researching. How do you google for a formula?!
Is there a program(preferrably freeware) that you can feed with your own formulas and play around to see if it generates any fractal images?

Any input is appreciated!


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: PieMan597 on August 31, 2016, 01:23:52 AM
Xaos meet you input your own formulas, it is free on Windows and Linux.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: 3dickulus on August 31, 2016, 02:14:36 AM
this nifty little proggy lets you enter your own color formulas and fractal formulas

(https://www.physcip.uni-stuttgart.de/pages/~phy11733/doc/quat.png)

main page...
English https://www.physcip.uni-stuttgart.de/pages/~phy11733/index_e.html
German https://www.physcip.uni-stuttgart.de/pages/~phy11733/

as I recall, it's a bit slow but the formula parser is really very cool, and the source code is available, not sure if there is a windows version  :-\



Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: TheRedshiftRider on August 31, 2016, 05:55:45 AM
Fractal zoomer:
https://sourceforge.net/projects/fractalzoomer/?source=directory

This application has a user formula feature.
(Side-note: I actually requested the feature because I needed it for something else. :D )


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: Chillheimer on August 31, 2016, 08:44:21 AM
thank you guys!
I tried xaos - obviously the formulas don't do anything special, all I get is a circle


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: PieMan597 on August 31, 2016, 06:05:55 PM
Here's a formula to try: (z^2+c)/(c^2+z)


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: lkmitch on August 31, 2016, 07:54:36 PM
Here's a Julia-type fractal based on Pieman's idea.  f(z) = (z^n+c)/(c^n+z), for n = -2.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: Adam Majewski on September 02, 2016, 07:19:14 PM
Great. How it was made ?


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: simon.snake on September 02, 2016, 09:55:04 PM
FractInt (for all its failings) does a reasonable job with its built-in formula parser.

I admit I use it to play with ideas (even if I have no idea if they'll work - they usually don't) to try to find interesting things.  That's how I found my 'Simonbrot' that people have been exploring.

The only problem with it is that because it was a DOS program you have to load your favourite text editor (notepad anyone) and create a .frm file containing your formulas.

This can be saved anywhere but by default FractInt looks in its own folder first.  I think that may also be configurable.

If you go down that route let me know so I can see if there's any way to assist.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: simon.snake on September 02, 2016, 10:15:41 PM
A rather plain circle in FractInt for both formulas too.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: lkmitch on September 07, 2016, 05:40:36 PM
Great. How it was made ?


I made it in Ultra Fractal.  Here is the formula.  If you don't use Ultra Fractal, you should be able to read the code and figure it out for the program that you use.  The Mandelbrot version is trickier, since finding a critical point for beginning the iteration is not trivial.


rational-julia {
;
; from pieman597
; http://www.fractalforums.com/general-discussion-b77/t24459/msg95653/#new
;
; based on f(z) = (z^2+c)/(c^2+z)
; generalize to any power
;
init:
  complex bottom=(0,0)
  complex c=@julparam
  complex cton=c^@power
  complex top=(0,0)
  complex z=#pixel
loop:
  top=z^@power+c
  bottom=z+cton
  z=top/bottom
bailout:
  |z|<@bailout
default:
  title="rational julia"
  complex param julparam
    caption="julia parameter"
    default=(0,1)
  endparam
  complex param power
    caption="power"
    default=2
  endparam
  float param bailout
    caption="bailout"
    default=1000
  endparam
switch:
  type="rational-mandelbrot"
  power=power
  bailout=bailout
}


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: Adam Majewski on October 07, 2016, 08:35:07 PM
can you put your image to commons ?
https://commons.wikimedia.org/wiki/Category:Julia_sets

It's very nice


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: LionHeart on April 18, 2017, 08:54:01 AM
Hi Simon,

I notice in your message: "Re: Do z-->z/c² or z-->z*c² create a fractal « Reply #8 on: September 02, 2016, 09:55:04 PM »" that you talk about the function parser in FRACTINT.

I have a windoze program with an on-screen parser based on the FRACTINT library. You may find it useful for playing with fractal formulae rather than all that tedious mucking about in hyperspace using text files interpreted in a Dossy program :)

It's a rough and ready program, but I have fun:

http://www.deleeuw.com.au/download/SetupManpWIN.exe (http://www.deleeuw.com.au/download/SetupManpWIN.exe)

If you actually decide to try it, press T and the direct formula parser is in the middle of the dialogue box.

Have fun.

Paul the LionHeart



Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: simon.snake on April 18, 2017, 10:22:48 PM
Hi Paul

I do believe I have your program installed (or at least on my laptop) so I have used it before.  What's the current version number? I've got v3.01j installed.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: LionHeart on April 18, 2017, 10:57:15 PM
Hi Simon,

The current version of ManpWIN (including SimonBrot) is 3.03a.

I hope you can get it. Let me know if you can't and we will find a way.

I tried to attach it to a message but got: "Your file is too large. The maximum attachment size allowed is 256 KB. "



Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: Chillheimer on April 18, 2017, 11:08:24 PM
I tried to attach it to a message but got: "Your file is too large. The maximum attachment size allowed is 256 KB. "

sorry for that, we currently face major problems with our server and are happy the forum is running at all. working on a solution - until then, please upload externally and share the link here.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: LionHeart on April 18, 2017, 11:26:26 PM
Thanks Chillheimer.

Let me know when I can attach my program as there may be others who want to play with it :)


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: Chillheimer on April 18, 2017, 11:45:31 PM
we'll post an announcement as soon as it works again.

until then, why not use a free hoster like https://wetransfer.com/


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: LionHeart on April 18, 2017, 11:52:24 PM
Thanks Chillheimer,

I have not heard of that site. If others have a problem, I'll give it a go.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: LionHeart on April 19, 2017, 12:01:10 AM
Hi Chillheimer,

It seems to work...

https://we.tl/XgsgNlwBmH (https://we.tl/XgsgNlwBmH)

The link will last a week.

Many thanks.



Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: clacker on April 26, 2017, 03:21:20 AM
I implemented this function as a Fragmentarium script for the z = (z^n+c)/(c^n+z) function that lets you play with the Julia values and vary the power from -4 to 4.  Here are some samples and the frag file.


Title: Re: Do z-->z/c² or z-->z*c² create a fractal
Post by: Adam Majewski on May 28, 2017, 09:49:27 AM
I made it in Ultra Fractal.  Here is the formula.  If you don't use Ultra Fractal, you should be able to read the code and figure it out for the program that you use.  The Mandelbrot version is trickier, since finding a critical point for beginning the iteration is not trivial.


rational-julia {
;
; from pieman597
; http://www.fractalforums.com/general-discussion-b77/t24459/msg95653/#new
;
; based on f(z) = (z^2+c)/(c^2+z)
; generalize to any power
;
init:
  complex bottom=(0,0)
  complex c=@julparam
  complex cton=c^@power
  complex top=(0,0)
  complex z=#pixel
loop:
  top=z^@power+c
  bottom=z+cton
  z=top/bottom
bailout:
  |z|<@bailout
default:
  title="rational julia"
  complex param julparam
    caption="julia parameter"
    default=(0,1)
  endparam
  complex param power
    caption="power"
    default=2
  endparam
  float param bailout
    caption="bailout"
    default=1000
  endparam
switch:
  type="rational-mandelbrot"
  power=power
  bailout=bailout
}


I have opend your formula in wine/UF5 but image is different
?