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Description: A different way of using double 2 angles :

If we get the angle around the 3rd axis giving:

x^2-y^2    2*x*y    huh???

And double the angle around the x axis using:

huh???      y^2-z^2     2*y*z

So if we take 2*x*y as the given "correct" new value for y then we can calculate the new z value such that both angles are maintained :

x^2 -y^2     2*x*y      4*x*y^2*z/(y^2-z^2)

Of course this gives a slight issue when the new angle around the x axis is 90 degrees i.e. when (y^2-z^2) is zero, but in such a case I've simply used 2*y*z as the new z value because in order to maintain the correct magnitude we have to fudge that anyway.

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Keywords: two angles 
Posted by: David Makin July 09, 2014, 03:38:52 AM

Rating: ***** by 1 members.

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David Makin
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July 09, 2014, 03:41:18 AM
Oops - the above is correct for doubling the angles, but I should have pointed out this is z^8+c using the above triplex method so of course both angles are multiplied by 8 in this case.

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